-0,2x^2-x+450=0

Solution for -0,2x^2-x+450=0 equation:

-0.2x^2-x+450=0

We add all the numbers together, and all the variables

-0.2x^2-1x+450=0

a = -0.2; b = -1; c = +450;
Δ = b2-4ac
Δ = -12-4·(-0.2)·450
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-19}{2*-0.2}=\frac{-18}{-0.4}
=+45
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+19}{2*-0.2}=\frac{20}{-0.4}
=-50
$